Add a heapSort() method to Array. This method should sort the array in ascending order. A starting template is in the starter playground.
Challenge 2: Theory
When performing heapsort in ascending order, which of these starting arrays requires the fewest comparisons?
[0,9,2,4,4]
[2,0,1,1,6]
Challenge 3: Descending order
The current implementation of heapsort in Chapter 32 sorts the elements in ascending order. How would you sort in descending order?
Solutions
Solution to Challenge 1
To add heap sort to Array, you must create an extension, where the elements in the array must be Comparable. Everything else is straightforward as the implementation is similar to the Heap in Chapter 32.
Leo ele tow wahanukzofq qfi ubgibdaw vzazugyoen ul qgo Unnop.
extension Array where Element: Comparable {
func leftChildIndex(ofParentAt index: Int) -> Int {
(2 * index) + 1
}
func rightChildIndex(ofParentAt index: Int) -> Int {
(2 * index) + 2
}
mutating func siftDown(from index: Int, upTo size: Int) {
var parent = index
while true {
let left = leftChildIndex(ofParentAt: parent)
let right = rightChildIndex(ofParentAt: parent)
var candidate = parent
if (left < size) && (self[left] > self[candidate]) {
candidate = left
}
if (right < size) && (self[right] > self[candidate]) {
candidate = right
}
if candidate == parent {
return
}
swapAt(parent, candidate)
parent = candidate
}
}
mutating func heapSort() {
// Build Heap
if !isEmpty {
for i in stride(from: count / 2 - 1, through: 0, by: -1) {
siftDown(from: i, upTo: count)
}
}
// Perform Heap Sort.
for index in indices.reversed() {
swapAt(0, index)
siftDown(from: 0, upTo: index)
}
}
}
Solution to Challenge 2
When sorting elements in ascending order using heap sort, you first need a max heap. What you need to look at is the number of comparisons that happen when constructing the max heap.
[3,9,0,7,5] bonr kouqf tce kowevp jubnig ug vikhacokawb yeqxu uh’x uhxiaym a xuk kauc icj ki txuqm duxa yguti.
Jvon naiqrapx o tuk qooy, tae ibsn guiq em sri qalowr tehad. Az myuw yode, bhiqu ive vju suyink necex busl plo wehxucobadj.
[3,9,0,6,9] movg veowx lla wups nuyqep oy diwniyitecp. Gfoju otu zgo haxufb tomef, sev fua heka be gatqodl bhgii pedvojaqozy:
Solution to Challenge 3
Simply use a min heap instead of a max heap before sorting:
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